-9x^2+6x+4=5

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Solution for -9x^2+6x+4=5 equation: 



-9x^2+6x+4=5

We move all terms to the left:

-9x^2+6x+4-(5)=0

We add all the numbers together, and all the variables

-9x^2+6x-1=0

a = -9; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-9)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{-18}=1/3$

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